File: 7vajonyas.swf-(5.75 MB, 1920x1080, Other)
[_] Imagine... Anonymous 08/10/15(Mon)16:09:01 No.2871754
Marked for deletion (old).
>> [_] Anonymous 08/10/15(Mon)17:16:11 No.2871820
Seven? Not quite. If we hypothesize that one vagina exists between every two legs, we would get:
2 legs = 1 vagina
3 = 3 (the jump here is akin to going from a line to a triangle)
4 = 5~6 (multiple diagonals may intersect at a center; vaginas overlap)
5 = 10
6 = 13~15 (the range increases for every even number of legs)
7 = 21
8 = 25- 28
And so on, until the amount of legs reaches an unspecified limit of the range your hips can hold
minus the space alloted for your torso (X - 2 legs, approximately). I call this the vagoo theorem.
>> [_] Anonymous 08/10/15(Mon)17:41:40 No.2871838
>>2871820
>maybe more
>> [_] Anonymous 08/10/15(Mon)19:30:11 No.2871909
https://www.youtube.com/watch?v=_nH6ya5g2-s
>> [_] Anonymous 08/10/15(Mon)19:51:38 No.2871922
>>2871820
This is contingent on the arrangement of the legs. Based on the assumption that two adjacent legs
will have a vagina between them, an arrangement of legs can have anywhere from n-1 to
(1/2)(n-1)(n) where n is the number of legs. If the legs are all arranged in a line, there will
only be n-1 vaginas, but if the legs are arranged like a regular polygon wth n vertices, then
there will be (1/2)(n-1)(n) vaginas assuming no overlap, which is the maximum number for a given
number of legs. Grimsby's statement was 7 vajonyas or maybe more, which is accurate. With 8 legs,
7 is the minimum number of vaginas. 28 is the maximum.
>> [_] Anonymous 08/10/15(Mon)20:17:07 No.2871941
It doesn't matter how many vaginas are there, you will still not get any